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(B) Using the vector triple product formula: $a 	imes (b 	imes c) = (a \cdot c)b - (a \cdot b)c$. Given that $a \perp b$,we have $a \cdot b = 0$. Gi

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$b$

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(B) Using the vector triple product formula: $a 	imes (b 	imes c) = (a \cdot c)b - (a \cdot b)c$. Given that $a \perp b$,we have $a \cdot b = 0$. Given that $a \parallel c$ and $a, c$ are unit vectors,$a \cdot c = \pm 1$. Since $a$ and $c$ are unit vectors,$a \cdot c = 1$ (if they are in the same direction) or $a \cdot c = -1$ (if they are in opposite directions). Assuming $a$ and $c$ are in the same direction,$a \cdot c = 1$. Substituting these values into the formula: $a 	imes (b 	imes c) = (1)b - (0)c = b$.

Given three unit vectors $a, b, c$ such that $a \perp b$ and $a \parallel c$,then $a \times (b \times c)$ is

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